Solve by Substitution -x+2y=4 , x-2y=4

$- x + 2 y = 4$ , $x - 2 y = 4$

Step 1

Add $2 y$ to both sides of the equation.

$x = 4 + 2 y$

$- x + 2 y = 4$

Step 2

Replace all occurrences of $x$ with $4 + 2 y$ in each equation.

Replace all occurrences of $x$ in $- x + 2 y = 4$ with $4 + 2 y$ .

$- (4 + 2 y) + 2 y = 4$

$x = 4 + 2 y$

Simplify the left side.

Simplify $- (4 + 2 y) + 2 y$ .

Simplify each term.

Apply the distributive property.

$- 1 \cdot 4 - (2 y) + 2 y = 4$

$x = 4 + 2 y$

Multiply $- 1$ by $4$ .

$- 4 - (2 y) + 2 y = 4$

$x = 4 + 2 y$

Multiply $2$ by $- 1$ .

$- 4 - 2 y + 2 y = 4$

$x = 4 + 2 y$

$- 4 - 2 y + 2 y = 4$

$x = 4 + 2 y$

Combine the opposite terms in $- 4 - 2 y + 2 y$ .

Add $- 2 y$ and $2 y$ .

$- 4 + 0 = 4$

$x = 4 + 2 y$

Add $- 4$ and $0$ .

$- 4 = 4$

$x = 4 + 2 y$

$- 4 = 4$

$x = 4 + 2 y$

$- 4 = 4$

$x = 4 + 2 y$

$- 4 = 4$

$x = 4 + 2 y$

$- 4 = 4$

$x = 4 + 2 y$

Step 3

Since $- 4 = 4$ is not true, there is no solution.

No solution

Step 4