Solve by Substitution x-2y=-4 , x+2y=8

$x - 2 y = - 4$ , $x + 2 y = 8$

Step 1

Add $2 y$ to both sides of the equation.

$x = - 4 + 2 y$

$x + 2 y = 8$

Step 2

Replace all occurrences of $x$ with $- 4 + 2 y$ in each equation.

Replace all occurrences of $x$ in $x + 2 y = 8$ with $- 4 + 2 y$ .

$(- 4 + 2 y) + 2 y = 8$

$x = - 4 + 2 y$

Simplify the left side.

Add $2 y$ and $2 y$ .

$- 4 + 4 y = 8$

$x = - 4 + 2 y$

$- 4 + 4 y = 8$

$x = - 4 + 2 y$

$- 4 + 4 y = 8$

$x = - 4 + 2 y$

Step 3

Solve for $y$ in $- 4 + 4 y = 8$ .

Move all terms not containing $y$ to the right side of the equation.

Add $4$ to both sides of the equation.

$4 y = 8 + 4$

$x = - 4 + 2 y$

Add $8$ and $4$ .

$4 y = 12$

$x = - 4 + 2 y$

$4 y = 12$

$x = - 4 + 2 y$

Divide each term in $4 y = 12$ by $4$ and simplify.

Divide each term in $4 y = 12$ by $4$ .

$\frac{4 y}{4} = \frac{12}{4}$

$x = - 4 + 2 y$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{12}{4}$

$x = - 4 + 2 y$

Divide $y$ by $1$ .

$y = \frac{12}{4}$

$x = - 4 + 2 y$

$y = \frac{12}{4}$

$x = - 4 + 2 y$

$y = \frac{12}{4}$

$x = - 4 + 2 y$

Simplify the right side.

Divide $12$ by $4$ .

$y = 3$

$x = - 4 + 2 y$

$y = 3$

$x = - 4 + 2 y$

$y = 3$

$x = - 4 + 2 y$

$y = 3$

$x = - 4 + 2 y$

Step 4

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = - 4 + 2 y$ with $3$ .

$x = - 4 + 2 (3)$

$y = 3$

Simplify the right side.

Simplify $- 4 + 2 (3)$ .

Multiply $2$ by $3$ .

$x = - 4 + 6$

$y = 3$

Add $- 4$ and $6$ .

$x = 2$

$y = 3$

$x = 2$

$y = 3$

$x = 2$

$y = 3$

$x = 2$

$y = 3$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, 3)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(2, 3)$

Equation Form:

$x = 2, y = 3$

Step 7

Solve by Substitution x-2y=-4 , x+2y=8

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