Solve by Substitution x-2y=8 , -x+2y=-8

$x - 2 y = 8$ , $- x + 2 y = - 8$

Step 1

Add $2 y$ to both sides of the equation.

$x = 8 + 2 y$

$- x + 2 y = - 8$

Step 2

Replace all occurrences of $x$ with $8 + 2 y$ in each equation.

Replace all occurrences of $x$ in $- x + 2 y = - 8$ with $8 + 2 y$ .

$- (8 + 2 y) + 2 y = - 8$

$x = 8 + 2 y$

Simplify the left side.

Simplify $- (8 + 2 y) + 2 y$ .

Simplify each term.

Apply the distributive property.

$- 1 \cdot 8 - (2 y) + 2 y = - 8$

$x = 8 + 2 y$

Multiply $- 1$ by $8$ .

$- 8 - (2 y) + 2 y = - 8$

$x = 8 + 2 y$

Multiply $2$ by $- 1$ .

$- 8 - 2 y + 2 y = - 8$

$x = 8 + 2 y$

$- 8 - 2 y + 2 y = - 8$

$x = 8 + 2 y$

Combine the opposite terms in $- 8 - 2 y + 2 y$ .

Add $- 2 y$ and $2 y$ .

$- 8 + 0 = - 8$

$x = 8 + 2 y$

Add $- 8$ and $0$ .

$- 8 = - 8$

$x = 8 + 2 y$

$- 8 = - 8$

$x = 8 + 2 y$

$- 8 = - 8$

$x = 8 + 2 y$

$- 8 = - 8$

$x = 8 + 2 y$

$- 8 = - 8$

$x = 8 + 2 y$

Step 3

Remove any equations from the system that are always true.

$x = 8 + 2 y$

Step 4