Solve by Substitution -x-3=y -3x-8y=4

$- x - 3 = y$ $- 3 x - 8 y = 4$

Rewrite the equation as $y = - x - 3$ .

$y = - x - 3$

$- 3 x - 8 y = 4$

Replace all occurrences of $y$ with $- x - 3$ in each equation.

Replace all occurrences of $y$ in $- 3 x - 8 y = 4$ with $- x - 3$ .

$- 3 x - 8 (- x - 3) = 4$

$y = - x - 3$

Simplify the left side.

Simplify $- 3 x - 8 (- x - 3)$ .

Simplify each term.

Apply the distributive property.

$- 3 x - 8 (- x) - 8 \cdot - 3 = 4$

$y = - x - 3$

Multiply $- 1$ by $- 8$ .

$- 3 x + 8 x - 8 \cdot - 3 = 4$

$y = - x - 3$

Multiply $- 8$ by $- 3$ .

$- 3 x + 8 x + 24 = 4$

$y = - x - 3$

$- 3 x + 8 x + 24 = 4$

$y = - x - 3$

Add $- 3 x$ and $8 x$ .

$5 x + 24 = 4$

$y = - x - 3$

$5 x + 24 = 4$

$y = - x - 3$

$5 x + 24 = 4$

$y = - x - 3$

$5 x + 24 = 4$

$y = - x - 3$

Solve for $x$ in $5 x + 24 = 4$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $24$ from both sides of the equation.

$5 x = 4 - 24$

$y = - x - 3$

Subtract $24$ from $4$ .

$5 x = - 20$

$y = - x - 3$

$5 x = - 20$

$y = - x - 3$

Divide each term in $5 x = - 20$ by $5$ and simplify.

Divide each term in $5 x = - 20$ by $5$ .

$\frac{5 x}{5} = \frac{- 20}{5}$

$y = - x - 3$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 20}{5}$

$y = - x - 3$

Divide $x$ by $1$ .

$x = \frac{- 20}{5}$

$y = - x - 3$

$x = \frac{- 20}{5}$

$y = - x - 3$

$x = \frac{- 20}{5}$

$y = - x - 3$

Simplify the right side.

Divide $- 20$ by $5$ .

$x = - 4$

$y = - x - 3$

$x = - 4$

$y = - x - 3$

$x = - 4$

$y = - x - 3$

$x = - 4$

$y = - x - 3$

Replace all occurrences of $x$ with $- 4$ in each equation.

Replace all occurrences of $x$ in $y = - x - 3$ with $- 4$ .

$y = - (- 4) - 3$

$x = - 4$

Simplify the right side.

Simplify $- (- 4) - 3$ .

Multiply $- 1$ by $- 4$ .

$y = 4 - 3$

$x = - 4$

Subtract $3$ from $4$ .

$y = 1$

$x = - 4$

$y = 1$

$x = - 4$

$y = 1$

$x = - 4$

$y = 1$

$x = - 4$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 4, 1)$

The result can be shown in multiple forms.

Point Form:

$(- 4, 1)$

Equation Form:

$x = - 4, y = 1$

Solve by Substitution -x-3=y -3x-8y=4

Related Questions

Support LCMGCF.com by disabling your adblocker.