Solve by Substitution x=4-5y and 2x+10y=8

$x = 4 - 5 y$ and $2 x + 10 y = 8$

Reorder $4$ and $- 5 y$ .

$x = - 5 y + 4$

$2 x + 10 y = 8$

Replace all occurrences of $x$ with $- 5 y + 4$ in each equation.

Replace all occurrences of $x$ in $2 x + 10 y = 8$ with $- 5 y + 4$ .

$2 (- 5 y + 4) + 10 y = 8$

$x = - 5 y + 4$

Simplify the left side.

Simplify $2 (- 5 y + 4) + 10 y$ .

Simplify each term.

Apply the distributive property.

$2 (- 5 y) + 2 \cdot 4 + 10 y = 8$

$x = - 5 y + 4$

Multiply $- 5$ by $2$ .

$- 10 y + 2 \cdot 4 + 10 y = 8$

$x = - 5 y + 4$

Multiply $2$ by $4$ .

$- 10 y + 8 + 10 y = 8$

$x = - 5 y + 4$

$- 10 y + 8 + 10 y = 8$

$x = - 5 y + 4$

Combine the opposite terms in $- 10 y + 8 + 10 y$ .

Add $- 10 y$ and $10 y$ .

$0 + 8 = 8$

$x = - 5 y + 4$

Add $0$ and $8$ .

$8 = 8$

$x = - 5 y + 4$

$8 = 8$

$x = - 5 y + 4$

$8 = 8$

$x = - 5 y + 4$

$8 = 8$

$x = - 5 y + 4$

$8 = 8$

$x = - 5 y + 4$

Remove any equations from the system that are always true.

$x = - 5 y + 4$

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