Solve by Substitution x=-4y , 3x+2y=20

$x = - 4 y$ , $3 x + 2 y = 20$

Step 1

Replace all occurrences of $x$ with $- 4 y$ in each equation.

Replace all occurrences of $x$ in $3 x + 2 y = 20$ with $- 4 y$ .

$3 (- 4 y) + 2 y = 20$

$x = - 4 y$

Simplify the left side.

Simplify $3 (- 4 y) + 2 y$ .

Multiply $- 4$ by $3$ .

$- 12 y + 2 y = 20$

$x = - 4 y$

Add $- 12 y$ and $2 y$ .

$- 10 y = 20$

$x = - 4 y$

$- 10 y = 20$

$x = - 4 y$

$- 10 y = 20$

$x = - 4 y$

$- 10 y = 20$

$x = - 4 y$

Step 2

Divide each term in $- 10 y = 20$ by $- 10$ and simplify.

Divide each term in $- 10 y = 20$ by $- 10$ .

$\frac{- 10 y}{- 10} = \frac{20}{- 10}$

$x = - 4 y$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 y}{- 10} = \frac{20}{- 10}$

$x = - 4 y$

Divide $y$ by $1$ .

$y = \frac{20}{- 10}$

$x = - 4 y$

$y = \frac{20}{- 10}$

$x = - 4 y$

$y = \frac{20}{- 10}$

$x = - 4 y$

Simplify the right side.

Divide $20$ by $- 10$ .

$y = - 2$

$x = - 4 y$

$y = - 2$

$x = - 4 y$

$y = - 2$

$x = - 4 y$

Step 3

Replace all occurrences of $y$ with $- 2$ in each equation.

Replace all occurrences of $y$ in $x = - 4 y$ with $- 2$ .

$x = - 4 \cdot - 2$

$y = - 2$

Simplify the right side.

Multiply $- 4$ by $- 2$ .

$x = 8$

$y = - 2$

$x = 8$

$y = - 2$

$x = 8$

$y = - 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(8, - 2)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(8, - 2)$

Equation Form:

$x = 8, y = - 2$

Step 6

Solve by Substitution x=-4y , 3x+2y=20

Related Questions

Support LCMGCF.com by disabling your adblocker.