Solve by Substitution x+4y=-8 , x-4y=-8

$x + 4 y = - 8$ , $x - 4 y = - 8$

Step 1

Subtract $4 y$ from both sides of the equation.

$x = - 8 - 4 y$

$x - 4 y = - 8$

Step 2

Replace all occurrences of $x$ with $- 8 - 4 y$ in each equation.

Replace all occurrences of $x$ in $x - 4 y = - 8$ with $- 8 - 4 y$ .

$(- 8 - 4 y) - 4 y = - 8$

$x = - 8 - 4 y$

Simplify the left side.

Subtract $4 y$ from $- 4 y$ .

$- 8 - 8 y = - 8$

$x = - 8 - 4 y$

$- 8 - 8 y = - 8$

$x = - 8 - 4 y$

$- 8 - 8 y = - 8$

$x = - 8 - 4 y$

Step 3

Solve for $y$ in $- 8 - 8 y = - 8$ .

Move all terms not containing $y$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- 8 y = - 8 + 8$

$x = - 8 - 4 y$

Add $- 8$ and $8$ .

$- 8 y = 0$

$x = - 8 - 4 y$

$- 8 y = 0$

$x = - 8 - 4 y$

Divide each term in $- 8 y = 0$ by $- 8$ and simplify.

Divide each term in $- 8 y = 0$ by $- 8$ .

$\frac{- 8 y}{- 8} = \frac{0}{- 8}$

$x = - 8 - 4 y$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 y}{- 8} = \frac{0}{- 8}$

$x = - 8 - 4 y$

Divide $y$ by $1$ .

$y = \frac{0}{- 8}$

$x = - 8 - 4 y$

$y = \frac{0}{- 8}$

$x = - 8 - 4 y$

$y = \frac{0}{- 8}$

$x = - 8 - 4 y$

Simplify the right side.

Divide $0$ by $- 8$ .

$y = 0$

$x = - 8 - 4 y$

$y = 0$

$x = - 8 - 4 y$

$y = 0$

$x = - 8 - 4 y$

$y = 0$

$x = - 8 - 4 y$

Step 4

Replace all occurrences of $y$ with $0$ in each equation.

Replace all occurrences of $y$ in $x = - 8 - 4 y$ with $0$ .

$x = - 8 - 4 \cdot 0$

$y = 0$

Simplify the right side.

Simplify $- 8 - 4 \cdot 0$ .

Multiply $- 4$ by $0$ .

$x = - 8 + 0$

$y = 0$

Add $- 8$ and $0$ .

$x = - 8$

$y = 0$

$x = - 8$

$y = 0$

$x = - 8$

$y = 0$

$x = - 8$

$y = 0$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 8, 0)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(- 8, 0)$

Equation Form:

$x = - 8, y = 0$

Step 7

Solve by Substitution x+4y=-8 , x-4y=-8

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