Solve by Substitution x-4y=8 , -x+4y=8

$x - 4 y = 8$ , $- x + 4 y = 8$

Step 1

Add $4 y$ to both sides of the equation.

$x = 8 + 4 y$

$- x + 4 y = 8$

Step 2

Replace all occurrences of $x$ with $8 + 4 y$ in each equation.

Replace all occurrences of $x$ in $- x + 4 y = 8$ with $8 + 4 y$ .

$- (8 + 4 y) + 4 y = 8$

$x = 8 + 4 y$

Simplify the left side.

Simplify $- (8 + 4 y) + 4 y$ .

Simplify each term.

Apply the distributive property.

$- 1 \cdot 8 - (4 y) + 4 y = 8$

$x = 8 + 4 y$

Multiply $- 1$ by $8$ .

$- 8 - (4 y) + 4 y = 8$

$x = 8 + 4 y$

Multiply $4$ by $- 1$ .

$- 8 - 4 y + 4 y = 8$

$x = 8 + 4 y$

$- 8 - 4 y + 4 y = 8$

$x = 8 + 4 y$

Combine the opposite terms in $- 8 - 4 y + 4 y$ .

Add $- 4 y$ and $4 y$ .

$- 8 + 0 = 8$

$x = 8 + 4 y$

Add $- 8$ and $0$ .

$- 8 = 8$

$x = 8 + 4 y$

$- 8 = 8$

$x = 8 + 4 y$

$- 8 = 8$

$x = 8 + 4 y$

$- 8 = 8$

$x = 8 + 4 y$

$- 8 = 8$

$x = 8 + 4 y$

Step 3

Since $- 8 = 8$ is not true, there is no solution.

No solution

Step 4