Solve by Substitution x=5-y x-y=3

$x = 5 - y$ $x - y = 3$

Step 1

Reorder $5$ and $- y$ .

$x = - y + 5$

$x - y = 3$

Step 2

Replace all occurrences of $x$ with $- y + 5$ in each equation.

Replace all occurrences of $x$ in $x - y = 3$ with $- y + 5$ .

$(- y + 5) - y = 3$

$x = - y + 5$

Simplify the left side.

Subtract $y$ from $- y$ .

$- 2 y + 5 = 3$

$x = - y + 5$

$- 2 y + 5 = 3$

$x = - y + 5$

$- 2 y + 5 = 3$

$x = - y + 5$

Step 3

Solve for $y$ in $- 2 y + 5 = 3$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 2 y = 3 - 5$

$x = - y + 5$

Subtract $5$ from $3$ .

$- 2 y = - 2$

$x = - y + 5$

$- 2 y = - 2$

$x = - y + 5$

Divide each term in $- 2 y = - 2$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 2$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2}$

$x = - y + 5$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2}$

$x = - y + 5$

Divide $y$ by $1$ .

$y = \frac{- 2}{- 2}$

$x = - y + 5$

$y = \frac{- 2}{- 2}$

$x = - y + 5$

$y = \frac{- 2}{- 2}$

$x = - y + 5$

Simplify the right side.

Divide $- 2$ by $- 2$ .

$y = 1$

$x = - y + 5$

$y = 1$

$x = - y + 5$

$y = 1$

$x = - y + 5$

$y = 1$

$x = - y + 5$

Step 4

Replace all occurrences of $y$ with $1$ in each equation.

Replace all occurrences of $y$ in $x = - y + 5$ with $1$ .

$x = - (1) + 5$

$y = 1$

Simplify the right side.

Simplify $- (1) + 5$ .

Multiply $- 1$ by $1$ .

$x = - 1 + 5$

$y = 1$

Add $- 1$ and $5$ .

$x = 4$

$y = 1$

$x = 4$

$y = 1$

$x = 4$

$y = 1$

$x = 4$

$y = 1$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(4, 1)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(4, 1)$

Equation Form:

$x = 4, y = 1$

Step 7

Solve by Substitution x=5-y x-y=3

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