Solve by Substitution x=5y+2 x-4y=5

$x = 5 y + 2$ $x - 4 y = 5$

Step 1

Replace all occurrences of $x$ with $5 y + 2$ in each equation.

Replace all occurrences of $x$ in $x - 4 y = 5$ with $5 y + 2$ .

$(5 y + 2) - 4 y = 5$

$x = 5 y + 2$

Simplify the left side.

Subtract $4 y$ from $5 y$ .

$y + 2 = 5$

$x = 5 y + 2$

$y + 2 = 5$

$x = 5 y + 2$

$y + 2 = 5$

$x = 5 y + 2$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$y = 5 - 2$

$x = 5 y + 2$

Subtract $2$ from $5$ .

$y = 3$

$x = 5 y + 2$

$y = 3$

$x = 5 y + 2$

Step 3

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = 5 y + 2$ with $3$ .

$x = 5 (3) + 2$

$y = 3$

Simplify the right side.

Simplify $5 (3) + 2$ .

Multiply $5$ by $3$ .

$x = 15 + 2$

$y = 3$

Add $15$ and $2$ .

$x = 17$

$y = 3$

$x = 17$

$y = 3$

$x = 17$

$y = 3$

$x = 17$

$y = 3$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(17, 3)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(17, 3)$

Equation Form:

$x = 17, y = 3$

Step 6

Solve by Substitution x=5y+2 x-4y=5

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