Solve by Substitution x-6y+4=0 y=-3

$x - 6 y + 4 = 0$ $y = - 3$

Step 1

Replace all occurrences of $y$ with $- 3$ in each equation.

Replace all occurrences of $y$ in $x - 6 y + 4 = 0$ with $- 3$ .

$x - 6 \cdot - 3 + 4 = 0$

$y = - 3$

Simplify the left side.

Simplify $x - 6 \cdot - 3 + 4$ .

Multiply $- 6$ by $- 3$ .

$x + 18 + 4 = 0$

$y = - 3$

Add $18$ and $4$ .

$x + 22 = 0$

$y = - 3$

$x + 22 = 0$

$y = - 3$

$x + 22 = 0$

$y = - 3$

$x + 22 = 0$

$y = - 3$

Step 2

Subtract $22$ from both sides of the equation.

$x = - 22$

$y = - 3$

Step 3

Solve the system of equations $x = - 22 y = - 3$ .

$x = - 22 y = - 3$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 22, - 3)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 22, - 3)$

Equation Form:

$x = - 22, y = - 3$

Step 6

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