Solve by Substitution -x+y=-10 10x+8=y

$- x + y = - 10$ $10 x + 8 = y$

Add $x$ to both sides of the equation.

$y = - 10 + x$

$10 x + 8 = y$

Replace all occurrences of $y$ with $- 10 + x$ in each equation.

Replace all occurrences of $y$ in $10 x + 8 = y$ with $- 10 + x$ .

$10 x + 8 = - 10 + x$

$y = - 10 + x$

Simplify the left side.

Remove parentheses.

$10 x + 8 = - 10 + x$

$y = - 10 + x$

$10 x + 8 = - 10 + x$

$y = - 10 + x$

$10 x + 8 = - 10 + x$

$y = - 10 + x$

Solve for $x$ in $10 x + 8 = - 10 + x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$10 x + 8 - x = - 10$

$y = - 10 + x$

Subtract $x$ from $10 x$ .

$9 x + 8 = - 10$

$y = - 10 + x$

$9 x + 8 = - 10$

$y = - 10 + x$

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$9 x = - 10 - 8$

$y = - 10 + x$

Subtract $8$ from $- 10$ .

$9 x = - 18$

$y = - 10 + x$

$9 x = - 18$

$y = - 10 + x$

Divide each term in $9 x = - 18$ by $9$ and simplify.

Divide each term in $9 x = - 18$ by $9$ .

$\frac{9 x}{9} = \frac{- 18}{9}$

$y = - 10 + x$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{- 18}{9}$

$y = - 10 + x$

Divide $x$ by $1$ .

$x = \frac{- 18}{9}$

$y = - 10 + x$

$x = \frac{- 18}{9}$

$y = - 10 + x$

$x = \frac{- 18}{9}$

$y = - 10 + x$

Simplify the right side.

Divide $- 18$ by $9$ .

$x = - 2$

$y = - 10 + x$

$x = - 2$

$y = - 10 + x$

$x = - 2$

$y = - 10 + x$

$x = - 2$

$y = - 10 + x$

Replace all occurrences of $x$ with $- 2$ in each equation.

Replace all occurrences of $x$ in $y = - 10 + x$ with $- 2$ .

$y = - 10 - 2$

$x = - 2$

Simplify $y = - 10 - 2$ .

Simplify the left side.

Remove parentheses.

$y = - 10 - 2$

$x = - 2$

$y = - 10 - 2$

$x = - 2$

Simplify the right side.

Subtract $2$ from $- 10$ .

$y = - 12$

$x = - 2$

$y = - 12$

$x = - 2$

$y = - 12$

$x = - 2$

$y = - 12$

$x = - 2$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, - 12)$

The result can be shown in multiple forms.

Point Form:

$(- 2, - 12)$

Equation Form:

$x = - 2, y = - 12$

Solve by Substitution -x+y=-10 10x+8=y

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