Solve by Substitution xy=6 , x^2+y^2=13

$x y = 6$ , $x^{2} + y^{2} = 13$

Step 1

Divide each term in $x y = 6$ by $y$ and simplify.

Divide each term in $x y = 6$ by $y$ .

$\frac{x y}{y} = \frac{6}{y}$

$x^{2} + y^{2} = 13$

Simplify the left side.

Cancel the common factor of $y$ .

Cancel the common factor.

$\frac{x y}{y} = \frac{6}{y}$

$x^{2} + y^{2} = 13$

Divide $x$ by $1$ .

$x = \frac{6}{y}$

$x^{2} + y^{2} = 13$

$x = \frac{6}{y}$

$x^{2} + y^{2} = 13$

$x = \frac{6}{y}$

$x^{2} + y^{2} = 13$

$x = \frac{6}{y}$

$x^{2} + y^{2} = 13$

Step 2

Replace all occurrences of $x$ with $\frac{6}{y}$ in each equation.

Replace all occurrences of $x$ in $x^{2} + y^{2} = 13$ with $\frac{6}{y}$ .

${(\frac{6}{y})}^{2} + y^{2} = 13$

$x = \frac{6}{y}$

Simplify the left side.

Simplify each term.

Apply the product rule to $\frac{6}{y}$ .

$\frac{6^{2}}{y^{2}} + y^{2} = 13$

$x = \frac{6}{y}$

Raise $6$ to the power of $2$ .

$\frac{36}{y^{2}} + y^{2} = 13$

$x = \frac{6}{y}$

$\frac{36}{y^{2}} + y^{2} = 13$

$x = \frac{6}{y}$

$\frac{36}{y^{2}} + y^{2} = 13$

$x = \frac{6}{y}$

$\frac{36}{y^{2}} + y^{2} = 13$

$x = \frac{6}{y}$

Step 3

Solve for $y$ in $\frac{36}{y^{2}} + y^{2} = 13$ .

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$y^{2}, 1, 1$

$x = \frac{6}{y}$

The LCM of one and any expression is the expression.

$y^{2}$

$x = \frac{6}{y}$

$y^{2}$

$x = \frac{6}{y}$

Multiply each term in $\frac{36}{y^{2}} + y^{2} = 13$ by $y^{2}$ to eliminate the fractions.

Multiply each term in $\frac{36}{y^{2}} + y^{2} = 13$ by $y^{2}$ .

$\frac{36}{y^{2}} \cdot y^{2} + y^{2} y^{2} = 13 y^{2}$

$x = \frac{6}{y}$

Simplify the left side.

Simplify each term.

Cancel the common factor of $y^{2}$ .

Cancel the common factor.

$\frac{36}{y^{2}} \cdot y^{2} + y^{2} y^{2} = 13 y^{2}$

$x = \frac{6}{y}$

Rewrite the expression.

$36 + y^{2} y^{2} = 13 y^{2}$

$x = \frac{6}{y}$

$36 + y^{2} y^{2} = 13 y^{2}$

$x = \frac{6}{y}$

Multiply $y^{2}$ by $y^{2}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$36 + y^{2 + 2} = 13 y^{2}$

$x = \frac{6}{y}$

Add $2$ and $2$ .

$36 + y^{4} = 13 y^{2}$

$x = \frac{6}{y}$

$36 + y^{4} = 13 y^{2}$

$x = \frac{6}{y}$

$36 + y^{4} = 13 y^{2}$

$x = \frac{6}{y}$

$36 + y^{4} = 13 y^{2}$

$x = \frac{6}{y}$

$36 + y^{4} = 13 y^{2}$

$x = \frac{6}{y}$

Solve the equation.

Subtract $13 y^{2}$ from both sides of the equation.

$36 + y^{4} - 13 y^{2} = 0$

$x = \frac{6}{y}$

Substitute $u = y^{2}$ into the equation. This will make the quadratic formula easy to use.

$u^{2} - 13 u + 36 = 0$

$u = y^{2}$

$x = \frac{6}{y}$

Factor $u^{2} - 13 u + 36$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $36$ and whose sum is $- 13$ .

$- 9, - 4$

$x = \frac{6}{y}$

Write the factored form using these integers.

$(u - 9) (u - 4) = 0$

$x = \frac{6}{y}$

$(u - 9) (u - 4) = 0$

$x = \frac{6}{y}$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$u - 9 = 0$

$u - 4 = 0$

$x = \frac{6}{y}$

Set $u - 9$ equal to $0$ and solve for $u$ .

Set $u - 9$ equal to $0$ .

$u - 9 = 0$

$x = \frac{6}{y}$

Add $9$ to both sides of the equation.

$u = 9$

$x = \frac{6}{y}$

$u = 9$

$x = \frac{6}{y}$

Set $u - 4$ equal to $0$ and solve for $u$ .

Set $u - 4$ equal to $0$ .

$u - 4 = 0$

$x = \frac{6}{y}$

Add $4$ to both sides of the equation.

$u = 4$

$x = \frac{6}{y}$

$u = 4$

$x = \frac{6}{y}$

The final solution is all the values that make $(u - 9) (u - 4) = 0$ true.

$u = 9, 4$

$x = \frac{6}{y}$

Substitute the real value of $u = y^{2}$ back into the solved equation.

$y^{2} = 9$

$y^{2} = 4$

$x = \frac{6}{y}$

Solve the first equation for $y$ .

$y^{2} = 9$

$x = \frac{6}{y}$

Solve the equation for $y$ .

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{9}$

$x = \frac{6}{y}$

Simplify $\pm \sqrt{9}$ .

Rewrite $9$ as $3^{2}$ .

$y = \pm \sqrt{3^{2}}$

$x = \frac{6}{y}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 3$

$x = \frac{6}{y}$

$y = \pm 3$

$x = \frac{6}{y}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 3$

$x = \frac{6}{y}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 3$

$x = \frac{6}{y}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 3, - 3$

$x = \frac{6}{y}$

$y = 3, - 3$

$x = \frac{6}{y}$

$y = 3, - 3$

$x = \frac{6}{y}$

Solve the second equation for $y$ .

$y^{2} = 4$

$x = \frac{6}{y}$

Solve the equation for $y$ .

Remove parentheses.

$y^{2} = 4$

$x = \frac{6}{y}$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{4}$

$x = \frac{6}{y}$

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$y = \pm \sqrt{2^{2}}$

$x = \frac{6}{y}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 2$

$x = \frac{6}{y}$

$y = \pm 2$

$x = \frac{6}{y}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 2$

$x = \frac{6}{y}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 2$

$x = \frac{6}{y}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 2, - 2$

$x = \frac{6}{y}$

$y = 2, - 2$

$x = \frac{6}{y}$

$y = 2, - 2$

$x = \frac{6}{y}$

The solution to $y^{4} - 13 y^{2} + 36 = 0$ is $y = 3, - 3, 2, - 2$ .

$y = 3, - 3, 2, - 2$

$x = \frac{6}{y}$

$y = 3, - 3, 2, - 2$

$x = \frac{6}{y}$

$y = 3, - 3, 2, - 2$

$x = \frac{6}{y}$

Step 4

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $3$ .

$x = \frac{6}{3}$

$y = 3$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

$y = 3$

$x = 2$

$y = 3$

$x = 2$

$y = 3$

Step 5

Replace all occurrences of $y$ with $- 3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $- 3$ .

$x = \frac{6}{- 3}$

$y = - 3$

Simplify the right side.

Divide $6$ by $- 3$ .

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

Step 6

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $3$ .

$x = \frac{6}{3}$

$y = 3$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

$y = 3$

$x = 2$

$y = 3$

$x = 2$

$y = 3$

Step 7

Replace all occurrences of $y$ with $- 3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $- 3$ .

$x = \frac{6}{- 3}$

$y = - 3$

Simplify the right side.

Divide $6$ by $- 3$ .

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

Step 8

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $2$ .

$x = \frac{6}{2}$

$y = 2$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3$

$y = 2$

$x = 3$

$y = 2$

$x = 3$

$y = 2$

Step 9

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $3$ .

$x = \frac{6}{3}$

$y = 3$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

$y = 3$

$x = 2$

$y = 3$

$x = 2$

$y = 3$

Step 10

Replace all occurrences of $y$ with $- 3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $- 3$ .

$x = \frac{6}{- 3}$

$y = - 3$

Simplify the right side.

Divide $6$ by $- 3$ .

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

$x = - 2$

$y = - 3$

Step 11

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $2$ .

$x = \frac{6}{2}$

$y = 2$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3$

$y = 2$

$x = 3$

$y = 2$

$x = 3$

$y = 2$

Step 12

Replace all occurrences of $y$ with $- 2$ in each equation.

Replace all occurrences of $y$ in $x = \frac{6}{y}$ with $- 2$ .

$x = \frac{6}{- 2}$

$y = - 2$

Simplify the right side.

Divide $6$ by $- 2$ .

$x = - 3$

$y = - 2$

$x = - 3$

$y = - 2$

$x = - 3$

$y = - 2$

Step 13

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, 3)$

$(- 2, - 3)$

$(3, 2)$

$(- 3, - 2)$

Step 14

The result can be shown in multiple forms.

Point Form:

$(2, 3), (- 2, - 3), (3, 2), (- 3, - 2)$

Equation Form:

$x = 2, y = 3$

$x = - 2, y = - 3$

$x = 3, y = 2$

$x = - 3, y = - 2$

Step 15

Solve by Substitution xy=6 , x^2+y^2=13

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