Solve by Substitution y=-1x-5 4x-8y=4

$y = - 1 x - 5$ $4 x - 8 y = 4$

Rewrite $- 1 x$ as $- x$ .

$y = - x - 5$

$4 x - 8 y = 4$

Replace all occurrences of $y$ with $- x - 5$ in each equation.

Replace all occurrences of $y$ in $4 x - 8 y = 4$ with $- x - 5$ .

$4 x - 8 (- x - 5) = 4$

$y = - x - 5$

Simplify the left side.

Simplify $4 x - 8 (- x - 5)$ .

Simplify each term.

Apply the distributive property.

$4 x - 8 (- x) - 8 \cdot - 5 = 4$

$y = - x - 5$

Multiply $- 1$ by $- 8$ .

$4 x + 8 x - 8 \cdot - 5 = 4$

$y = - x - 5$

Multiply $- 8$ by $- 5$ .

$4 x + 8 x + 40 = 4$

$y = - x - 5$

$4 x + 8 x + 40 = 4$

$y = - x - 5$

Add $4 x$ and $8 x$ .

$12 x + 40 = 4$

$y = - x - 5$

$12 x + 40 = 4$

$y = - x - 5$

$12 x + 40 = 4$

$y = - x - 5$

$12 x + 40 = 4$

$y = - x - 5$

Solve for $x$ in $12 x + 40 = 4$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $40$ from both sides of the equation.

$12 x = 4 - 40$

$y = - x - 5$

Subtract $40$ from $4$ .

$12 x = - 36$

$y = - x - 5$

$12 x = - 36$

$y = - x - 5$

Divide each term in $12 x = - 36$ by $12$ and simplify.

Divide each term in $12 x = - 36$ by $12$ .

$\frac{12 x}{12} = \frac{- 36}{12}$

$y = - x - 5$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 x}{12} = \frac{- 36}{12}$

$y = - x - 5$

Divide $x$ by $1$ .

$x = \frac{- 36}{12}$

$y = - x - 5$

$x = \frac{- 36}{12}$

$y = - x - 5$

$x = \frac{- 36}{12}$

$y = - x - 5$

Simplify the right side.

Divide $- 36$ by $12$ .

$x = - 3$

$y = - x - 5$

$x = - 3$

$y = - x - 5$

$x = - 3$

$y = - x - 5$

$x = - 3$

$y = - x - 5$

Replace all occurrences of $x$ with $- 3$ in each equation.

Replace all occurrences of $x$ in $y = - x - 5$ with $- 3$ .

$y = - (- 3) - 5$

$x = - 3$

Simplify the right side.

Simplify $- (- 3) - 5$ .

Multiply $- 1$ by $- 3$ .

$y = 3 - 5$

$x = - 3$

Subtract $5$ from $3$ .

$y = - 2$

$x = - 3$

$y = - 2$

$x = - 3$

$y = - 2$

$x = - 3$

$y = - 2$

$x = - 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 3, - 2)$

The result can be shown in multiple forms.

Point Form:

$(- 3, - 2)$

Equation Form:

$x = - 3, y = - 2$

Solve by Substitution y=-1x-5 4x-8y=4

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