Solve by Substitution y=-2 , 4x-3y=18

$y = - 2$ , $4 x - 3 y = 18$

Step 1

Replace all occurrences of $y$ with $- 2$ in each equation.

Replace all occurrences of $y$ in $4 x - 3 y = 18$ with $- 2$ .

$4 x - 3 \cdot - 2 = 18$

$y = - 2$

Simplify the left side.

Multiply $- 3$ by $- 2$ .

$4 x + 6 = 18$

$y = - 2$

$4 x + 6 = 18$

$y = - 2$

$4 x + 6 = 18$

$y = - 2$

Step 2

Solve for $x$ in $4 x + 6 = 18$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$4 x = 18 - 6$

$y = - 2$

Subtract $6$ from $18$ .

$4 x = 12$

$y = - 2$

$4 x = 12$

$y = - 2$

Divide each term in $4 x = 12$ by $4$ and simplify.

Divide each term in $4 x = 12$ by $4$ .

$\frac{4 x}{4} = \frac{12}{4}$

$y = - 2$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{12}{4}$

$y = - 2$

Divide $x$ by $1$ .

$x = \frac{12}{4}$

$y = - 2$

$x = \frac{12}{4}$

$y = - 2$

$x = \frac{12}{4}$

$y = - 2$

Simplify the right side.

Divide $12$ by $4$ .

$x = 3$

$y = - 2$

$x = 3$

$y = - 2$

$x = 3$

$y = - 2$

$x = 3$

$y = - 2$

Step 3

Solve the system of equations $x = 3 y = - 2$ .

$x = 3 y = - 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(3, - 2)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(3, - 2)$

Equation Form:

$x = 3, y = - 2$

Step 6

Solve by Substitution y=-2 , 4x-3y=18

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