Solve by Substitution y=2x-10 , y=4x-8

$y = 2 x - 10$ , $y = 4 x - 8$

Step 1

Eliminate the equal sides of each equation and combine.

$2 x - 10 = 4 x - 8$

Step 2

Solve $2 x - 10 = 4 x - 8$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$2 x - 10 - 4 x = - 8$

Subtract $4 x$ from $2 x$ .

$- 2 x - 10 = - 8$

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- 2 x = - 8 + 10$

Add $- 8$ and $10$ .

$- 2 x = 2$

Divide each term in $- 2 x = 2$ by $- 2$ and simplify.

Divide each term in $- 2 x = 2$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{2}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{2}{- 2}$

Divide $x$ by $1$ .

$x = \frac{2}{- 2}$

Simplify the right side.

Divide $2$ by $- 2$ .

$x = - 1$

Step 3

Evaluate $y$ when $x = - 1$ .

Substitute $- 1$ for $x$ .

$y = 4 (- 1) - 8$

Simplify $4 (- 1) - 8$ .

Multiply $4$ by $- 1$ .

$y = - 4 - 8$

Subtract $8$ from $- 4$ .

$y = - 12$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, - 12)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 1, - 12)$

Equation Form:

$x = - 1, y = - 12$

Step 6

Solve by Substitution y=2x-10 , y=4x-8

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