Solve by Substitution y=3x+14 y=x

$y = 3 x + 14$ $y = x$

Eliminate the equal sides of each equation and combine.

$3 x + 14 = x$

Solve $3 x + 14 = x$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 x + 14 - x = 0$

Subtract $x$ from $3 x$ .

$2 x + 14 = 0$

Subtract $14$ from both sides of the equation.

$2 x = - 14$

Divide each term in $2 x = - 14$ by $2$ and simplify.

Divide each term in $2 x = - 14$ by $2$ .

$\frac{2 x}{2} = \frac{- 14}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 14}{2}$

Divide $x$ by $1$ .

$x = \frac{- 14}{2}$

Simplify the right side.

Divide $- 14$ by $2$ .

$x = - 7$

Evaluate $y$ when $x = - 7$ .

Substitute $- 7$ for $x$ .

$y = - 7$

Remove parentheses.

$y = - 7$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 7, - 7)$

The result can be shown in multiple forms.

Point Form:

$(- 7, - 7)$

Equation Form:

$x = - 7, y = - 7$