Solve by Substitution y=-3x+4 y=x

$y = - 3 x + 4$ $y = x$

Step 1

Eliminate the equal sides of each equation and combine.

$- 3 x + 4 = x$

Step 2

Solve $- 3 x + 4 = x$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$- 3 x + 4 - x = 0$

Subtract $x$ from $- 3 x$ .

$- 4 x + 4 = 0$

Subtract $4$ from both sides of the equation.

$- 4 x = - 4$

Divide each term in $- 4 x = - 4$ by $- 4$ and simplify.

Divide each term in $- 4 x = - 4$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{- 4}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{- 4}{- 4}$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 4}$

Simplify the right side.

Divide $- 4$ by $- 4$ .

$x = 1$

Step 3

Evaluate $y$ when $x = 1$ .

Substitute $1$ for $x$ .

$y = 1$

Remove parentheses.

$y = 1$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(1, 1)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(1, 1)$

Equation Form:

$x = 1, y = 1$

Step 6