Solve by Substitution y=4+x y=-5x+16

$y = 4 + x$ $y = - 5 x + 16$

Eliminate the equal sides of each equation and combine.

$4 + x = - 5 x + 16$

Solve $4 + x = - 5 x + 16$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Add $5 x$ to both sides of the equation.

$4 + x + 5 x = 16$

Add $x$ and $5 x$ .

$4 + 6 x = 16$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$6 x = 16 - 4$

Subtract $4$ from $16$ .

$6 x = 12$

Divide each term in $6 x = 12$ by $6$ and simplify.

Divide each term in $6 x = 12$ by $6$ .

$\frac{6 x}{6} = \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{12}{6}$

Divide $x$ by $1$ .

$x = \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$x = 2$

Evaluate $y$ when $x = 2$ .

Substitute $2$ for $x$ .

$y = - 5 \cdot 2 + 16$

Substitute $2$ for $x$ in $y = - 5 \cdot 2 + 16$ and solve for $y$ .

Remove parentheses.

$y = - 5 \cdot 2 + 16$

Simplify $- 5 \cdot 2 + 16$ .

Multiply $- 5$ by $2$ .

$y = - 10 + 16$

Add $- 10$ and $16$ .

$y = 6$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, 6)$

The result can be shown in multiple forms.

Point Form:

$(2, 6)$

Equation Form:

$x = 2, y = 6$