Solve by Substitution y=-4x y=x+5

$y = - 4 x$ $y = x + 5$

Eliminate the equal sides of each equation and combine.

$- 4 x = x + 5$

Solve $- 4 x = x + 5$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$- 4 x - x = 5$

Subtract $x$ from $- 4 x$ .

$- 5 x = 5$

Divide each term in $- 5 x = 5$ by $- 5$ and simplify.

Divide each term in $- 5 x = 5$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{5}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{5}{- 5}$

Divide $x$ by $1$ .

$x = \frac{5}{- 5}$

Simplify the right side.

Divide $5$ by $- 5$ .

$x = - 1$

Evaluate $y$ when $x = - 1$ .

Substitute $- 1$ for $x$ .

$y = (- 1) + 5$

Substitute $- 1$ for $x$ in $y = (- 1) + 5$ and solve for $y$ .

Remove parentheses.

$y = - 1 + 5$

Remove parentheses.

$y = (- 1) + 5$

Add $- 1$ and $5$ .

$y = 4$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, 4)$

The result can be shown in multiple forms.

Point Form:

$(- 1, 4)$

Equation Form:

$x = - 1, y = 4$