Solve by Substitution y=-5 , 5x+4y=-20

$y = - 5$ , $5 x + 4 y = - 20$

Step 1

Replace all occurrences of $y$ with $- 5$ in each equation.

Replace all occurrences of $y$ in $5 x + 4 y = - 20$ with $- 5$ .

$5 x + 4 (- 5) = - 20$

$y = - 5$

Simplify the left side.

Multiply $4$ by $- 5$ .

$5 x - 20 = - 20$

$y = - 5$

$5 x - 20 = - 20$

$y = - 5$

$5 x - 20 = - 20$

$y = - 5$

Step 2

Solve for $x$ in $5 x - 20 = - 20$ .

Move all terms not containing $x$ to the right side of the equation.

Add $20$ to both sides of the equation.

$5 x = - 20 + 20$

$y = - 5$

Add $- 20$ and $20$ .

$5 x = 0$

$y = - 5$

$5 x = 0$

$y = - 5$

Divide each term in $5 x = 0$ by $5$ and simplify.

Divide each term in $5 x = 0$ by $5$ .

$\frac{5 x}{5} = \frac{0}{5}$

$y = - 5$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{0}{5}$

$y = - 5$

Divide $x$ by $1$ .

$x = \frac{0}{5}$

$y = - 5$

$x = \frac{0}{5}$

$y = - 5$

$x = \frac{0}{5}$

$y = - 5$

Simplify the right side.

Divide $0$ by $5$ .

$x = 0$

$y = - 5$

$x = 0$

$y = - 5$

$x = 0$

$y = - 5$

$x = 0$

$y = - 5$

Step 3

Solve the system of equations $x = 0 y = - 5$ .

$x = 0 y = - 5$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, - 5)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(0, - 5)$

Equation Form:

$x = 0, y = - 5$

Step 6

Solve by Substitution y=-5 , 5x+4y=-20

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