Solve by Substitution y=6x and 2x+3y=-20

$y = 6 x$ and $2 x + 3 y = - 20$

Replace all occurrences of $y$ with $6 x$ in each equation.

Replace all occurrences of $y$ in $2 x + 3 y = - 20$ with $6 x$ .

$2 x + 3 (6 x) = - 20$

$y = 6 x$

Simplify the left side.

Simplify $2 x + 3 (6 x)$ .

Multiply $6$ by $3$ .

$2 x + 18 x = - 20$

$y = 6 x$

Add $2 x$ and $18 x$ .

$20 x = - 20$

$y = 6 x$

$20 x = - 20$

$y = 6 x$

$20 x = - 20$

$y = 6 x$

$20 x = - 20$

$y = 6 x$

Divide each term in $20 x = - 20$ by $20$ and simplify.

Divide each term in $20 x = - 20$ by $20$ .

$\frac{20 x}{20} = \frac{- 20}{20}$

$y = 6 x$

Simplify the left side.

Cancel the common factor of $20$ .

Cancel the common factor.

$\frac{20 x}{20} = \frac{- 20}{20}$

$y = 6 x$

Divide $x$ by $1$ .

$x = \frac{- 20}{20}$

$y = 6 x$

$x = \frac{- 20}{20}$

$y = 6 x$

$x = \frac{- 20}{20}$

$y = 6 x$

Simplify the right side.

Divide $- 20$ by $20$ .

$x = - 1$

$y = 6 x$

$x = - 1$

$y = 6 x$

$x = - 1$

$y = 6 x$

Replace all occurrences of $x$ with $- 1$ in each equation.

Replace all occurrences of $x$ in $y = 6 x$ with $- 1$ .

$y = 6 (- 1)$

$x = - 1$

Simplify the right side.

Multiply $6$ by $- 1$ .

$y = - 6$

$x = - 1$

$y = - 6$

$x = - 1$

$y = - 6$

$x = - 1$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, - 6)$

The result can be shown in multiple forms.

Point Form:

$(- 1, - 6)$

Equation Form:

$x = - 1, y = - 6$

Solve by Substitution y=6x and 2x+3y=-20

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