Solve by Substitution y=-7x y=9x+32

$y = - 7 x$ $y = 9 x + 32$

Eliminate the equal sides of each equation and combine.

$- 7 x = 9 x + 32$

Solve $- 7 x = 9 x + 32$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$- 7 x - 9 x = 32$

Subtract $9 x$ from $- 7 x$ .

$- 16 x = 32$

Divide each term in $- 16 x = 32$ by $- 16$ and simplify.

Divide each term in $- 16 x = 32$ by $- 16$ .

$\frac{- 16 x}{- 16} = \frac{32}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 x}{- 16} = \frac{32}{- 16}$

Divide $x$ by $1$ .

$x = \frac{32}{- 16}$

Simplify the right side.

Divide $32$ by $- 16$ .

$x = - 2$

Evaluate $y$ when $x = - 2$ .

Substitute $- 2$ for $x$ .

$y = 9 (- 2) + 32$

Simplify $9 (- 2) + 32$ .

Multiply $9$ by $- 2$ .

$y = - 18 + 32$

Add $- 18$ and $32$ .

$y = 14$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, 14)$

The result can be shown in multiple forms.

Point Form:

$(- 2, 14)$

Equation Form:

$x = - 2, y = 14$