Solve by Substitution y=x+2 and 3x+3y=6

$y = x + 2$ and $3 x + 3 y = 6$

Replace all occurrences of $y$ with $x + 2$ in each equation.

Replace all occurrences of $y$ in $3 x + 3 y = 6$ with $x + 2$ .

$3 x + 3 (x + 2) = 6$

$y = x + 2$

Simplify the left side.

Simplify $3 x + 3 (x + 2)$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 x + 3 \cdot 2 = 6$

$y = x + 2$

Multiply $3$ by $2$ .

$3 x + 3 x + 6 = 6$

$y = x + 2$

$3 x + 3 x + 6 = 6$

$y = x + 2$

Add $3 x$ and $3 x$ .

$6 x + 6 = 6$

$y = x + 2$

$6 x + 6 = 6$

$y = x + 2$

$6 x + 6 = 6$

$y = x + 2$

$6 x + 6 = 6$

$y = x + 2$

Solve for $x$ in $6 x + 6 = 6$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$6 x = 6 - 6$

$y = x + 2$

Subtract $6$ from $6$ .

$6 x = 0$

$y = x + 2$

$6 x = 0$

$y = x + 2$

Divide each term in $6 x = 0$ by $6$ and simplify.

Divide each term in $6 x = 0$ by $6$ .

$\frac{6 x}{6} = \frac{0}{6}$

$y = x + 2$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{0}{6}$

$y = x + 2$

Divide $x$ by $1$ .

$x = \frac{0}{6}$

$y = x + 2$

$x = \frac{0}{6}$

$y = x + 2$

$x = \frac{0}{6}$

$y = x + 2$

Simplify the right side.

Divide $0$ by $6$ .

$x = 0$

$y = x + 2$

$x = 0$

$y = x + 2$

$x = 0$

$y = x + 2$

$x = 0$

$y = x + 2$

Replace all occurrences of $x$ with $0$ in each equation.

Replace all occurrences of $x$ in $y = x + 2$ with $0$ .

$y = (0) + 2$

$x = 0$

Simplify the right side.

Add $0$ and $2$ .

$y = 2$

$x = 0$

$y = 2$

$x = 0$

$y = 2$

$x = 0$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, 2)$

The result can be shown in multiple forms.

Point Form:

$(0, 2)$

Equation Form:

$x = 0, y = 2$

Solve by Substitution y=x+2 and 3x+3y=6

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