Solve by Substitution y=-x+3 , 2y+2x=4

$y = - x + 3$ , $2 y + 2 x = 4$

Step 1

Replace all occurrences of $y$ with $- x + 3$ in each equation.

Replace all occurrences of $y$ in $2 y + 2 x = 4$ with $- x + 3$ .

$2 (- x + 3) + 2 x = 4$

$y = - x + 3$

Simplify the left side.

Simplify $2 (- x + 3) + 2 x$ .

Simplify each term.

Apply the distributive property.

$2 (- x) + 2 \cdot 3 + 2 x = 4$

$y = - x + 3$

Multiply $- 1$ by $2$ .

$- 2 x + 2 \cdot 3 + 2 x = 4$

$y = - x + 3$

Multiply $2$ by $3$ .

$- 2 x + 6 + 2 x = 4$

$y = - x + 3$

$- 2 x + 6 + 2 x = 4$

$y = - x + 3$

Combine the opposite terms in $- 2 x + 6 + 2 x$ .

Add $- 2 x$ and $2 x$ .

$0 + 6 = 4$

$y = - x + 3$

Add $0$ and $6$ .

$6 = 4$

$y = - x + 3$

$6 = 4$

$y = - x + 3$

$6 = 4$

$y = - x + 3$

$6 = 4$

$y = - x + 3$

$6 = 4$

$y = - x + 3$

Step 2

Since $6 = 4$ is not true, there is no solution.

No solution

Step 3

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