Solve for a 10a-a-9a+3a+2=5

$10 a - a - 9 a + 3 a + 2 = 5$

Simplify $10 a - a - 9 a + 3 a + 2$ .

Subtract $a$ from $10 a$ .

$9 a - 9 a + 3 a + 2 = 5$

Subtract $9 a$ from $9 a$ .

$0 + 3 a + 2 = 5$

Add $0$ and $3 a$ .

$3 a + 2 = 5$

Move all terms not containing $a$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$3 a = 5 - 2$

Subtract $2$ from $5$ .

$3 a = 3$

Divide each term in $3 a = 3$ by $3$ and simplify.

Divide each term in $3 a = 3$ by $3$ .

$\frac{3 a}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 a}{3} = \frac{3}{3}$

Divide $a$ by $1$ .

$a = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$a = 1$