Solve for a 2a+3(3a-5)=-4

$2 a + 3 (3 a - 5) = - 4$

Simplify $2 a + 3 (3 a - 5)$ .

Simplify each term.

Apply the distributive property.

$2 a + 3 (3 a) + 3 \cdot - 5 = - 4$

Multiply $3$ by $3$ .

$2 a + 9 a + 3 \cdot - 5 = - 4$

Multiply $3$ by $- 5$ .

$2 a + 9 a - 15 = - 4$

Add $2 a$ and $9 a$ .

$11 a - 15 = - 4$

Move all terms not containing $a$ to the right side of the equation.

Add $15$ to both sides of the equation.

$11 a = - 4 + 15$

Add $- 4$ and $15$ .

$11 a = 11$

Divide each term in $11 a = 11$ by $11$ and simplify.

Divide each term in $11 a = 11$ by $11$ .

$\frac{11 a}{11} = \frac{11}{11}$

Simplify the left side.

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{11 a}{11} = \frac{11}{11}$

Divide $a$ by $1$ .

$a = \frac{11}{11}$

Simplify the right side.

Divide $11$ by $11$ .

$a = 1$