Solve for a 3/2(a-10)=-3

$\frac{3}{2} (a - 10) = - 3$

Multiply both sides of the equation by $\frac{2}{3}$ .

$\frac{2}{3} (\frac{3}{2} \cdot (a - 10)) = \frac{2}{3} \cdot - 3$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{2}{3} (\frac{3}{2} \cdot (a - 10))$ .

Apply the distributive property.

$\frac{2}{3} (\frac{3}{2} a + \frac{3}{2} \cdot - 10) = \frac{2}{3} \cdot - 3$

Combine $\frac{3}{2}$ and $a$ .

$\frac{2}{3} (\frac{3 a}{2} + \frac{3}{2} \cdot - 10) = \frac{2}{3} \cdot - 3$

Cancel the common factor of $2$ .

Factor $2$ out of $- 10$ .

$\frac{2}{3} (\frac{3 a}{2} + \frac{3}{2} \cdot (2 (- 5))) = \frac{2}{3} \cdot - 3$

Cancel the common factor.

$\frac{2}{3} (\frac{3 a}{2} + \frac{3}{2} \cdot (2 \cdot - 5)) = \frac{2}{3} \cdot - 3$

Rewrite the expression.

$\frac{2}{3} (\frac{3 a}{2} + 3 \cdot - 5) = \frac{2}{3} \cdot - 3$

Multiply $3$ by $- 5$ .

$\frac{2}{3} (\frac{3 a}{2} - 15) = \frac{2}{3} \cdot - 3$

Apply the distributive property.

$\frac{2}{3} \cdot \frac{3 a}{2} + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{3} \cdot \frac{3 a}{2} + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Rewrite the expression.

$\frac{1}{3} (3 a) + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Cancel the common factor of $3$ .

Factor $3$ out of $3 a$ .

$\frac{1}{3} (3 (a)) + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Cancel the common factor.

$\frac{1}{3} (3 a) + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Rewrite the expression.

$a + \frac{2}{3} \cdot - 15 = \frac{2}{3} \cdot - 3$

Cancel the common factor of $3$ .

Factor $3$ out of $- 15$ .

$a + \frac{2}{3} \cdot (3 (- 5)) = \frac{2}{3} \cdot - 3$

Cancel the common factor.

$a + \frac{2}{3} \cdot (3 \cdot - 5) = \frac{2}{3} \cdot - 3$

Rewrite the expression.

$a + 2 \cdot - 5 = \frac{2}{3} \cdot - 3$

Multiply $2$ by $- 5$ .

$a - 10 = \frac{2}{3} \cdot - 3$

Simplify the right side.

Simplify $\frac{2}{3} \cdot - 3$ .

Cancel the common factor of $3$ .

Factor $3$ out of $- 3$ .

$a - 10 = \frac{2}{3} \cdot (3 (- 1))$

Cancel the common factor.

$a - 10 = \frac{2}{3} \cdot (3 \cdot - 1)$

Rewrite the expression.

$a - 10 = 2 \cdot - 1$

Multiply $2$ by $- 1$ .

$a - 10 = - 2$

Move all terms not containing $a$ to the right side of the equation.

Add $10$ to both sides of the equation.

$a = - 2 + 10$

Add $- 2$ and $10$ .

$a = 8$

Solve for a 3/2(a-10)=-3

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