Solve for a 3(4-a)=2(a+6)

$3 (4 - a) = 2 (a + 6)$

Simplify $3 (4 - a)$ .

Start simplifying.

$0 + 0 + 3 (4 - a) = 2 (a + 6)$

Simplify by adding zeros.

$3 (4 - a) = 2 (a + 6)$

Apply the distributive property.

$3 \cdot 4 + 3 (- a) = 2 (a + 6)$

Multiply.

Multiply $3$ by $4$ .

$12 + 3 (- a) = 2 (a + 6)$

Multiply $- 1$ by $3$ .

$12 - 3 a = 2 (a + 6)$

Simplify $2 (a + 6)$ .

Apply the distributive property.

$12 - 3 a = 2 a + 2 \cdot 6$

Multiply $2$ by $6$ .

$12 - 3 a = 2 a + 12$

Move all terms containing $a$ to the left side of the equation.

Subtract $2 a$ from both sides of the equation.

$12 - 3 a - 2 a = 12$

Subtract $2 a$ from $- 3 a$ .

$12 - 5 a = 12$

Move all terms not containing $a$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- 5 a = 12 - 12$

Subtract $12$ from $12$ .

$- 5 a = 0$

Divide each term in $- 5 a = 0$ by $- 5$ and simplify.

Divide each term in $- 5 a = 0$ by $- 5$ .

$\frac{- 5 a}{- 5} = \frac{0}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 a}{- 5} = \frac{0}{- 5}$

Divide $a$ by $1$ .

$a = \frac{0}{- 5}$

Simplify the right side.

Divide $0$ by $- 5$ .

$a = 0$