Solve for a -3a-3=-2n+3p

$- 3 a - 3 = - 2 n + 3 p$

Step 1

Add $3$ to both sides of the equation.

$- 3 a = - 2 n + 3 p + 3$

Step 2

Divide each term in $- 3 a = - 2 n + 3 p + 3$ by $- 3$ and simplify.

Divide each term in $- 3 a = - 2 n + 3 p + 3$ by $- 3$ .

$\frac{- 3 a}{- 3} = \frac{- 2 n}{- 3} + \frac{3 p}{- 3} + \frac{3}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 a}{- 3} = \frac{- 2 n}{- 3} + \frac{3 p}{- 3} + \frac{3}{- 3}$

Divide $a$ by $1$ .

$a = \frac{- 2 n}{- 3} + \frac{3 p}{- 3} + \frac{3}{- 3}$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$a = \frac{(2) n}{3} + \frac{3 p}{- 3} + \frac{3}{- 3}$

Cancel the common factor of $3$ and $- 3$ .

Factor $3$ out of $3 p$ .

$a = \frac{2 n}{3} + \frac{3 (p)}{- 3} + \frac{3}{- 3}$

Move the negative one from the denominator of $\frac{p}{- 1}$ .

$a = \frac{2 n}{3} - 1 \cdot p + \frac{3}{- 3}$

Rewrite $- 1 \cdot p$ as $- p$ .

$a = \frac{2 n}{3} - p + \frac{3}{- 3}$

Divide $3$ by $- 3$ .

$a = \frac{2 n}{3} - p - 1$