Solve for a 4a-3+2a=7a-2

$4 a - 3 + 2 a = 7 a - 2$

Add $4 a$ and $2 a$ .

$6 a - 3 = 7 a - 2$

Move all terms containing $a$ to the left side of the equation.

Subtract $7 a$ from both sides of the equation.

$6 a - 3 - 7 a = - 2$

Subtract $7 a$ from $6 a$ .

$- a - 3 = - 2$

Move all terms not containing $a$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- a = - 2 + 3$

Add $- 2$ and $3$ .

$- a = 1$

Divide each term in $- a = 1$ by $- 1$ and simplify.

Divide each term in $- a = 1$ by $- 1$ .

$\frac{- a}{- 1} = \frac{1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{a}{1} = \frac{1}{- 1}$

Divide $a$ by $1$ .

$a = \frac{1}{- 1}$

Simplify the right side.

Divide $1$ by $- 1$ .

$a = - 1$