Solve for a 4x=(a+b)/(8c)

$4 x = \frac{a + b}{8 c}$

Rewrite the equation as $\frac{a + b}{8 c} = 4 x$ .

$\frac{a + b}{8 c} = 4 x$

Multiply both sides by $8 c$ .

$\frac{a + b}{8 c} (8 c) = 4 x (8 c)$

Simplify.

Simplify the left side.

Simplify $\frac{a + b}{8 c} (8 c)$ .

Rewrite using the commutative property of multiplication.

$8 \frac{a + b}{8 c} c = 4 x (8 c)$

Cancel the common factor of $8$ .

Factor $8$ out of $8 c$ .

$8 \frac{a + b}{8 (c)} c = 4 x (8 c)$

Cancel the common factor.

$8 \frac{a + b}{8 c} c = 4 x (8 c)$

Rewrite the expression.

$\frac{a + b}{c} c = 4 x (8 c)$

Cancel the common factor of $c$ .

Cancel the common factor.

$\frac{a + b}{c} c = 4 x (8 c)$

Rewrite the expression.

$a + b = 4 x (8 c)$

Simplify the right side.

Simplify $4 x (8 c)$ .

Rewrite using the commutative property of multiplication.

$a + b = 4 \cdot 8 x c$

Multiply $4$ by $8$ .

$a + b = 32 x c$

Subtract $b$ from both sides of the equation.

$a = 32 x c - b$