Solve for a 5a+4(3a-8)=4+13a

$5 a + 4 (3 a - 8) = 4 + 13 a$

Step 1

Simplify $5 a + 4 (3 a - 8)$ .

Simplify each term.

Apply the distributive property.

$5 a + 4 (3 a) + 4 \cdot - 8 = 4 + 13 a$

Multiply $3$ by $4$ .

$5 a + 12 a + 4 \cdot - 8 = 4 + 13 a$

Multiply $4$ by $- 8$ .

$5 a + 12 a - 32 = 4 + 13 a$

Add $5 a$ and $12 a$ .

$17 a - 32 = 4 + 13 a$

Step 2

Move all terms containing $a$ to the left side of the equation.

Subtract $13 a$ from both sides of the equation.

$17 a - 32 - 13 a = 4$

Subtract $13 a$ from $17 a$ .

$4 a - 32 = 4$

Step 3

Move all terms not containing $a$ to the right side of the equation.

Add $32$ to both sides of the equation.

$4 a = 4 + 32$

Add $4$ and $32$ .

$4 a = 36$

Step 4

Divide each term in $4 a = 36$ by $4$ and simplify.

Divide each term in $4 a = 36$ by $4$ .

$\frac{4 a}{4} = \frac{36}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 a}{4} = \frac{36}{4}$

Divide $a$ by $1$ .

$a = \frac{36}{4}$

Simplify the right side.

Divide $36$ by $4$ .

$a = 9$