Solve for a -8=8(-3+a)

$- 8 = 8 (- 3 + a)$

Step 1

Rewrite the equation as $8 (- 3 + a) = - 8$ .

$8 (- 3 + a) = - 8$

Step 2

Divide each term in $8 (- 3 + a) = - 8$ by $8$ and simplify.

Divide each term in $8 (- 3 + a) = - 8$ by $8$ .

$\frac{8 (- 3 + a)}{8} = \frac{- 8}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 (- 3 + a)}{8} = \frac{- 8}{8}$

Divide $- 3 + a$ by $1$ .

$- 3 + a = \frac{- 8}{8}$

Simplify the right side.

Divide $- 8$ by $8$ .

$- 3 + a = - 1$

Step 3

Move all terms not containing $a$ to the right side of the equation.

Add $3$ to both sides of the equation.

$a = - 1 + 3$

Add $- 1$ and $3$ .

$a = 2$