Solve for a 8a-(1+5a)=4(3a-11)-20

$8 a - (1 + 5 a) = 4 (3 a - 11) - 20$

Step 1

Simplify $8 a - (1 + 5 a)$ .

Simplify each term.

Apply the distributive property.

$8 a - 1 \cdot 1 - (5 a) = 4 (3 a - 11) - 20$

Multiply $- 1$ by $1$ .

$8 a - 1 - (5 a) = 4 (3 a - 11) - 20$

Multiply $5$ by $- 1$ .

$8 a - 1 - 5 a = 4 (3 a - 11) - 20$

Subtract $5 a$ from $8 a$ .

$3 a - 1 = 4 (3 a - 11) - 20$

Step 2

Simplify $4 (3 a - 11) - 20$ .

Simplify each term.

Apply the distributive property.

$3 a - 1 = 4 (3 a) + 4 \cdot - 11 - 20$

Multiply $3$ by $4$ .

$3 a - 1 = 12 a + 4 \cdot - 11 - 20$

Multiply $4$ by $- 11$ .

$3 a - 1 = 12 a - 44 - 20$

Subtract $20$ from $- 44$ .

$3 a - 1 = 12 a - 64$

Step 3

Move all terms containing $a$ to the left side of the equation.

Subtract $12 a$ from both sides of the equation.

$3 a - 1 - 12 a = - 64$

Subtract $12 a$ from $3 a$ .

$- 9 a - 1 = - 64$

Step 4

Move all terms not containing $a$ to the right side of the equation.

Add $1$ to both sides of the equation.

$- 9 a = - 64 + 1$

Add $- 64$ and $1$ .

$- 9 a = - 63$

Step 5

Divide each term in $- 9 a = - 63$ by $- 9$ and simplify.

Divide each term in $- 9 a = - 63$ by $- 9$ .

$\frac{- 9 a}{- 9} = \frac{- 63}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 a}{- 9} = \frac{- 63}{- 9}$

Divide $a$ by $1$ .

$a = \frac{- 63}{- 9}$

Simplify the right side.

Divide $- 63$ by $- 9$ .

$a = 7$

Solve for a 8a-(1+5a)=4(3a-11)-20

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