Solve for a a(3x+4)=b+18x

$a (3 x + 4) = b + 18 x$

Divide each term in $a (3 x + 4) = b + 18 x$ by $3 x + 4$ .

$\frac{a (3 x + 4)}{3 x + 4} = \frac{b}{3 x + 4} + \frac{18 x}{3 x + 4}$

Simplify the left side.

Cancel the common factor of $3 x + 4$ .

Cancel the common factor.

$\frac{a (3 x + 4)}{3 x + 4} = \frac{b}{3 x + 4} + \frac{18 x}{3 x + 4}$

Divide $a$ by $1$ .

$a = \frac{b}{3 x + 4} + \frac{18 x}{3 x + 4}$

Simplify the right side.

Combine the numerators over the common denominator.

$a = \frac{b + 18 x}{3 x + 4}$