Solve for a a(n)=(2)^(n-1)

$a (n) = {(2)}^{n - 1}$

Step 1

Divide each term in $a n = 2^{n - 1}$ by $n$ .

$\frac{a n}{n} = \frac{2^{n - 1}}{n}$

Step 2

Simplify the left side.

Cancel the common factor of $n$ .

Cancel the common factor.

$\frac{a n}{n} = \frac{2^{n - 1}}{n}$

Divide $a$ by $1$ .

$a = \frac{2^{n - 1}}{n}$

$a = \frac{2^{n - 1}}{n}$

$a = \frac{2^{n - 1}}{n}$

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