Solve for a a(x+3)<5x+15-x

$a (x + 3) < 5 x + 15 - x$

Subtract $x$ from $5 x$ .

$a (x + 3) < 4 x + 15$

Divide each term in $a (x + 3) < 4 x + 15$ by $x + 3$ and simplify.

Divide each term in $a (x + 3) < 4 x + 15$ by $x + 3$ .

$\frac{a (x + 3)}{x + 3} < \frac{4 x}{x + 3} + \frac{15}{x + 3}$

Simplify the left side.

Cancel the common factor of $x + 3$ .

Cancel the common factor.

$\frac{a (x + 3)}{x + 3} < \frac{4 x}{x + 3} + \frac{15}{x + 3}$

Divide $a$ by $1$ .

$a < \frac{4 x}{x + 3} + \frac{15}{x + 3}$

Simplify the right side.

Combine the numerators over the common denominator.

$a < \frac{4 x + 15}{x + 3}$