Solve for a (b+3f)a=g

$(b + 3 f) a = g$

Step 1

Divide each term in $(b + 3 f) a = g$ by $b + 3 f$ .

$\frac{(b + 3 f) a}{b + 3 f} = \frac{g}{b + 3 f}$

Step 2

Simplify the left side.

Cancel the common factor of $b + 3 f$ .

Cancel the common factor.

$\frac{(b + 3 f) a}{b + 3 f} = \frac{g}{b + 3 f}$

Divide $a$ by $1$ .

$a = \frac{g}{b + 3 f}$