Solve for A d-4h=3QA

$d - 4 h = 3 Q A$

Step 1

Rewrite the equation as $3 Q A = d - 4 h$ .

$3 Q A = d - 4 h$

Step 2

Divide each term in $3 Q A = d - 4 h$ by $3 Q$ and simplify.

Divide each term in $3 Q A = d - 4 h$ by $3 Q$ .

$\frac{3 Q A}{3 Q} = \frac{d}{3 Q} + \frac{- 4 h}{3 Q}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 Q A}{3 Q} = \frac{d}{3 Q} + \frac{- 4 h}{3 Q}$

Rewrite the expression.

$\frac{Q A}{Q} = \frac{d}{3 Q} + \frac{- 4 h}{3 Q}$

Cancel the common factor of $Q$ .

Cancel the common factor.

$\frac{Q A}{Q} = \frac{d}{3 Q} + \frac{- 4 h}{3 Q}$

Divide $A$ by $1$ .

$A = \frac{d}{3 Q} + \frac{- 4 h}{3 Q}$

Simplify the right side.

Move the negative in front of the fraction.

$A = \frac{d}{3 Q} - \frac{4 h}{3 Q}$