Solve for a g+1/4Ua=B

$g + \frac{1}{4} U a = B$

Step 1

Multiply $\frac{1}{4} (U a)$ .

Combine $U$ and $\frac{1}{4}$ .

$g + \frac{U}{4} a = B$

Combine $\frac{U}{4}$ and $a$ .

$g + \frac{U a}{4} = B$

$g + \frac{U a}{4} = B$

Step 2

Subtract $g$ from both sides of the equation.

$\frac{U a}{4} = B - g$

Step 3

Multiply both sides of the equation by $4$ .

$4 \frac{U a}{4} = 4 (B - g)$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$4 \frac{U a}{4} = 4 (B - g)$

Rewrite the expression.

$U a = 4 (B - g)$

$U a = 4 (B - g)$

$U a = 4 (B - g)$

Simplify the right side.

Simplify $4 (B - g)$ .

Apply the distributive property.

$U a = 4 B + 4 (- g)$

Multiply $- 1$ by $4$ .

$U a = 4 B - 4 g$

$U a = 4 B - 4 g$

$U a = 4 B - 4 g$

$U a = 4 B - 4 g$

Step 5

Divide each term in $U a = 4 B - 4 g$ by $U$ and simplify.

Divide each term in $U a = 4 B - 4 g$ by $U$ .

$\frac{U a}{U} = \frac{4 B}{U} + \frac{- 4 g}{U}$

Simplify the left side.

Cancel the common factor of $U$ .

Cancel the common factor.

$\frac{U a}{U} = \frac{4 B}{U} + \frac{- 4 g}{U}$

Divide $a$ by $1$ .

$a = \frac{4 B}{U} + \frac{- 4 g}{U}$

$a = \frac{4 B}{U} + \frac{- 4 g}{U}$

$a = \frac{4 B}{U} + \frac{- 4 g}{U}$

Simplify the right side.

Move the negative in front of the fraction.

$a = \frac{4 B}{U} - \frac{4 g}{U}$

$a = \frac{4 B}{U} - \frac{4 g}{U}$

$a = \frac{4 B}{U} - \frac{4 g}{U}$

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