Solve for a -g+3/4a=y

$- g + \frac{3}{4} a = y$

Step 1

Combine $\frac{3}{4}$ and $a$ .

$- g + \frac{3 a}{4} = y$

Step 2

Add $g$ to both sides of the equation.

$\frac{3 a}{4} = y + g$

Step 3

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} \cdot \frac{3 a}{4} = \frac{4}{3} (y + g)$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} \cdot \frac{3 a}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{3} \cdot \frac{3 a}{4} = \frac{4}{3} (y + g)$

Rewrite the expression.

$\frac{1}{3} (3 a) = \frac{4}{3} (y + g)$

Cancel the common factor of $3$ .

Factor $3$ out of $3 a$ .

$\frac{1}{3} (3 (a)) = \frac{4}{3} (y + g)$

Cancel the common factor.

$\frac{1}{3} (3 a) = \frac{4}{3} (y + g)$

Rewrite the expression.

$a = \frac{4}{3} (y + g)$

Simplify the right side.

Simplify $\frac{4}{3} (y + g)$ .

Apply the distributive property.

$a = \frac{4}{3} y + \frac{4}{3} g$

Combine $\frac{4}{3}$ and $y$ .

$a = \frac{4 y}{3} + \frac{4}{3} g$

Combine $\frac{4}{3}$ and $g$ .

$a = \frac{4 y}{3} + \frac{4 g}{3}$

Step 5

Reorder $\frac{4 y}{3}$ and $\frac{4 g}{3}$ .

$a = \frac{4 g}{3} + \frac{4 y}{3}$