Solve for a H=3da+f

$H = 3 d a + f$

Step 1

Rewrite the equation as $3 d a + f = H$ .

$3 d a + f = H$

Step 2

Subtract $f$ from both sides of the equation.

$3 d a = H - f$

Step 3

Divide each term in $3 d a = H - f$ by $3 d$ and simplify.

Divide each term in $3 d a = H - f$ by $3 d$ .

$\frac{3 d a}{3 d} = \frac{H}{3 d} + \frac{- f}{3 d}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 d a}{3 d} = \frac{H}{3 d} + \frac{- f}{3 d}$

Rewrite the expression.

$\frac{d a}{d} = \frac{H}{3 d} + \frac{- f}{3 d}$

Cancel the common factor of $d$ .

Cancel the common factor.

$\frac{d a}{d} = \frac{H}{3 d} + \frac{- f}{3 d}$

Divide $a$ by $1$ .

$a = \frac{H}{3 d} + \frac{- f}{3 d}$

Simplify the right side.

Move the negative in front of the fraction.

$a = \frac{H}{3 d} - \frac{f}{3 d}$