Solve for a h=k+ log of a/c

Rewrite the equation as ${\displaystyle k+\log \left(\frac{a}{c}\right)=h}$.

Subtract ${\displaystyle k}$ from both sides of the equation.

Rewrite ${\displaystyle \log \left(\frac{a}{c}\right)=h-k}$ in exponential form using the definition of a logarithm. If ${\displaystyle x}$ and ${\displaystyle b}$ are positive real numbers and ${\displaystyle b\ne 1}$, then ${\displaystyle {\log }_b\left(x\right)=y}$ is equivalent to ${\displaystyle b^y=x}$.