Solve for A hA=2-bA

$hA = 2 - b A$

Step 1

Rewrite the equation as $2 - b A = hA$ .

$2 - b A = hA$

Step 2

Subtract $2$ from both sides of the equation.

$- b A = hA - 2$

Step 3

Divide each term in $- b A = hA - 2$ by $- 1 b$ and simplify.

Divide each term in $- b A = hA - 2$ by $- 1 b$ .

$\frac{- b A}{- 1 b} = \frac{hA}{- 1 b} + \frac{- 2}{- 1 b}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b A}{b} = \frac{hA}{- 1 b} + \frac{- 2}{- 1 b}$

Cancel the common factor of $b$ .

Cancel the common factor.

$\frac{b A}{b} = \frac{hA}{- 1 b} + \frac{- 2}{- 1 b}$

Divide $A$ by $1$ .

$A = \frac{hA}{- 1 b} + \frac{- 2}{- 1 b}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$A = - \frac{hA}{b} + \frac{- 2}{- 1 b}$

Dividing two negative values results in a positive value.

$A = - \frac{hA}{b} + \frac{2}{b}$

Step 4

Rewrite the expression.

$A = - \frac{1}{b} hA + \frac{2}{b}$