Solve for a n=b(-h^2+a)

$n = b (- h^{2} + a)$

Step 1

Rewrite the equation as $b (- h^{2} + a) = n$ .

$b (- h^{2} + a) = n$

Step 2

Divide each term in $b (- h^{2} + a) = n$ by $b$ and simplify.

Divide each term in $b (- h^{2} + a) = n$ by $b$ .

$\frac{b (- h^{2} + a)}{b} = \frac{n}{b}$

Simplify the left side.

Cancel the common factor of $b$ .

Cancel the common factor.

$\frac{b (- h^{2} + a)}{b} = \frac{n}{b}$

Divide $- h^{2} + a$ by $1$ .

$- h^{2} + a = \frac{n}{b}$

Step 3

Add $h^{2}$ to both sides of the equation.

$a = \frac{n}{b} + h^{2}$