Solve for a t=(F^3+G)a

$t = (F^{3} + G) a$

Step 1

Rewrite the equation as $(F^{3} + G) a = t$ .

$(F^{3} + G) a = t$

Step 2

Divide each term in $(F^{3} + G) a = t$ by $F^{3} + G$ and simplify.

Divide each term in $(F^{3} + G) a = t$ by $F^{3} + G$ .

$\frac{(F^{3} + G) a}{F^{3} + G} = \frac{t}{F^{3} + G}$

Simplify the left side.

Cancel the common factor of $F^{3} + G$ .

Cancel the common factor.

$\frac{(F^{3} + G) a}{F^{3} + G} = \frac{t}{F^{3} + G}$

Divide $a$ by $1$ .

$a = \frac{t}{F^{3} + G}$