Solve for a w=3(2a+b)-4

$w = 3 (2 a + b) - 4$

Step 1

Rewrite the equation as $3 (2 a + b) - 4 = w$ .

$3 (2 a + b) - 4 = w$

Step 2

Simplify each term.

Apply the distributive property.

$3 (2 a) + 3 b - 4 = w$

Multiply $2$ by $3$ .

$6 a + 3 b - 4 = w$

Step 3

Move all terms not containing $a$ to the right side of the equation.

Subtract $3 b$ from both sides of the equation.

$6 a - 4 = w - 3 b$

Add $4$ to both sides of the equation.

$6 a = w - 3 b + 4$

Step 4

Divide each term in $6 a = w - 3 b + 4$ by $6$ and simplify.

Divide each term in $6 a = w - 3 b + 4$ by $6$ .

$\frac{6 a}{6} = \frac{w}{6} + \frac{- 3 b}{6} + \frac{4}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 a}{6} = \frac{w}{6} + \frac{- 3 b}{6} + \frac{4}{6}$

Divide $a$ by $1$ .

$a = \frac{w}{6} + \frac{- 3 b}{6} + \frac{4}{6}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 3$ and $6$ .

Factor $3$ out of $- 3 b$ .

$a = \frac{w}{6} + \frac{3 (- b)}{6} + \frac{4}{6}$

Cancel the common factors.

Factor $3$ out of $6$ .

$a = \frac{w}{6} + \frac{3 (- b)}{3 (2)} + \frac{4}{6}$

Cancel the common factor.

$a = \frac{w}{6} + \frac{3 (- b)}{3 \cdot 2} + \frac{4}{6}$

Rewrite the expression.

$a = \frac{w}{6} + \frac{- b}{2} + \frac{4}{6}$

Move the negative in front of the fraction.

$a = \frac{w}{6} - \frac{b}{2} + \frac{4}{6}$

Cancel the common factor of $4$ and $6$ .

Factor $2$ out of $4$ .

$a = \frac{w}{6} - \frac{b}{2} + \frac{2 (2)}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$a = \frac{w}{6} - \frac{b}{2} + \frac{2 \cdot 2}{2 \cdot 3}$

Cancel the common factor.

$a = \frac{w}{6} - \frac{b}{2} + \frac{2 \cdot 2}{2 \cdot 3}$

Rewrite the expression.

$a = \frac{w}{6} - \frac{b}{2} + \frac{2}{3}$

Solve for a w=3(2a+b)-4

Related Questions

Support LCMGCF.com by disabling your adblocker.