Solve for a x^2 cube root of x^4=x^a

$x^{2} \sqrt[3]{x^{4}} = x^{a}$

Rewrite the equation as $x^{a} = x^{2} \sqrt[3]{x^{4}}$ .

$x^{a} = x^{2} \sqrt[3]{x^{4}}$

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x^{4}}$ as $x^{\frac{4}{3}}$ .

$x^{a} = x^{2} x^{\frac{4}{3}}$

Multiply $x^{2}$ by $x^{\frac{4}{3}}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{a} = x^{2 + \frac{4}{3}}$

To write $2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x^{a} = x^{2 \cdot \frac{3}{3} + \frac{4}{3}}$

Combine $2$ and $\frac{3}{3}$ .

$x^{a} = x^{\frac{2 \cdot 3}{3} + \frac{4}{3}}$

Combine the numerators over the common denominator.

$x^{a} = x^{\frac{2 \cdot 3 + 4}{3}}$

Simplify the numerator.

Multiply $2$ by $3$ .

$x^{a} = x^{\frac{6 + 4}{3}}$

Add $6$ and $4$ .

$x^{a} = x^{\frac{10}{3}}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$a = \frac{10}{3}$

The result can be shown in multiple forms.

Exact Form:

$a = \frac{10}{3}$

Decimal Form:

$a = 3.\overline{3}$

Mixed Number Form:

$a = 3 \frac{1}{3}$