Solve for a1 a_1=(1^2-1)/(1^2+1)

$a_{1} = \frac{1^{2} - 1}{1^{2} + 1}$

Simplify the numerator.

One to any power is one.

$a_{1} = \frac{1 - 1}{1^{2} + 1}$

Subtract $1$ from $1$ .

$a_{1} = \frac{0}{1^{2} + 1}$

$a_{1} = \frac{0}{1^{2} + 1}$

Simplify the denominator.

One to any power is one.

$a_{1} = \frac{0}{1 + 1}$

Add $1$ and $1$ .

$a_{1} = \frac{0}{2}$

$a_{1} = \frac{0}{2}$

Divide $0$ by $2$ .

$a_{1} = 0$

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